The paper “ Network Fundamentals with Cisco - Accommodating Hosts in the Student Networks” is an informative assignment on logic & programming. Subnet1: 16= 00010000 11001000.11001000.00010000.00000000 188.8.131.52/23.Subnet2: 18= 00010010 11001000.11001000.00010010.0000000 184.108.40.206/23. Students NetworkWe are to accommodate at least 8000 hosts in the student network. The available IP address to use is 220.127.116.11/19. We have borrowed 1 bit from 18.104.22.168/18 to accommodate 8000 hosts hence the network portion has 19 bits and host portion 13 bits. The network prefix is /19. The subnet mask in Decimal=255.255.224.0The subnet mask in binary= 11111111.11111111.11100000.00000000 Number of Subnet= 21=2 SubnetsNumber of Hosts= 213-2=8,190 Hosts per subnetNetwork 22.214.171.124/19 with one borrowed address we have 2 Subnets starting from (0, 32) 126.96.36.199/19 11001000.
11001000. 00100000.00000000 Network Portion Host Portion Lowest Host Address: The lowest host address is always 1 greater than a network address11001000. 11001000. 00100000.0000000000000.00000001 All host bits except the last significant address are all 0s: 0+0+0+0+0+0+0+1=1. With the lowest bit of the host address set to a 1, the address is 188.8.131.52 so, the lowest host address is 184.108.40.206 Broadcast AddressAll host bits are set to 1.11001000. 11001000. 00100000.0000000011111.11111111 This gives 32+16+8+4+2+1. 128+64+32+16+8+4+2+1==63.255==Broadcast address is 220.127.116.11 Highest Host addressThe highest host address is 1 less broadcast address.
This gives 18.104.22.168 Administration NetworkThe administration needs 2000 hosts. We take the next available IP address which is 22.214.171.124/21. We have borrowed 1 bit for the network portion. Therefore the network prefix is /21. The subnet address is 126.96.36.199 /21.The subnet mask in binary = 11111111.11111111.11111000.0000000Subnet mask in Decimal= 255.255.248.0Number of Subnets= 21= 2 SubnetsHosts per Subnet = 211-2= 2,046 HostsLowest Host IP address: The lowest host address is always 1 greater than a network address11001000. 11001000. 00010000.00000000000.0000000111001000. 11001000. 00010000.00000001 This gives 188.8.131.52Broadcast addressAll host bits are set to 1.Therefore, 11001000.
11001000. 00010000.00000000111.11111111 This gives 16+4+2+1.128+64+32+16+8+4+2+1= 23.255Broadcast Address is 184.108.40.206 Highest AddressThe highest host address is 1 less broadcast address. This gives 220.127.116.11 Therefore, the subnet address is 18.104.22.168 /21, subnet mask 255.255.248.0, Broadcast address 22.214.171.124, and lowest and highest IP address is 126.96.36.199 and 188.8.131.52 respectively. Academic Staff NetworkTo accommodate 400 hosts we use IP 184.108.40.206/23 and have 2 bits borrowed. Subnet in binary= 11111111.11111111.11111110.00000000Subnet in Decimal= 255.255.254.0Subnets=22=4 Number of Hosts per subnet= 29-2= 510 Lowest IP address11001000. 11001000. 00010010.000000000.0000000111001000. 11001000. 00010010.00000001=220.127.116.11 Broadcast address: Set all host bits to 111001000. 11001000. 00010010.000000001.11111111=16+2+1.128+64+32+16+8+2+1=19.255=18.104.22.168 Highest Host addressThe highest host address is 1 less broadcast address 22.214.171.124 Therefore, the subnet address is 126.96.36.199/23, subnet mask 255.255.254.0, Broadcast address 188.8.131.52 and lowest and highest address being 184.108.40.206 and 220.127.116.11 respectively. Computer Lab NetworkWe borrow 1 Bit from 18.104.22.168/19 to accommodate 4000 hosts.
The network Prefix is /20 22.214.171.124/20. Subnet Mask in Decimal is 255.255.240The subnet mask in Binary is 11111111.11111111.11110000.00000000Subnets = 21= 2 SubnetsHosts per Subnet = 212-2= 4,094 Lowest Host address11001000. 11001000. 00000000.000000000000.0000000111001000. 11001000. 00000000.00000001The lowest IP address is 126.96.36.199 Broadcast address11001000. 11001000. 00000000.00000000(Binary)1111.1111111111001000. 11001000. 00001111.11111111The broadcast address is 188.8.131.52 Highest host addressThe highest host address is 1 less broadcast addressHence it is 184.108.40.206 Therefore, the subnet address is 220.127.116.11/20, subnet mask 255.255.240, Broadcast address 18.104.22.168, and lowest and highest address being 22.214.171.124 and 126.96.36.199 respectively. Question 4(a) Source MAC address and destination MAC address The destination MAC addresses are stored in Ethernet Frame in Destination Address field where 6 bytes are allocated to it and the source MAC address is stored in the Source Address field which also has 6 bytes allocated. (b) Source IP address and Destination IP address The destination IP address and the Source IP address is stored in the IP packet header.
Source IP address and destination IP address are usually dealt with in Layer 3 of the OSI Model (Network Layer). (c) Source MAC address, Destination MAC Address, Source IP Address, and Destination IP address Leaving the Client Source MAC address: 00D0.AB12.CD71 Destination MAC Address: 0011.ABCD. 554C